The discussers ask why a hyperelastic model was employed. There are several reasons why using an hyper-elastic model is preferable. Probably the most important one is that closed cycles do not produce nor dissipate energy [17, 8]; instead, using a hypoelastic model, closed cycles may produce or dissipate energy, which is inconsistent with the definition of an elastic deformation path. As stressed by Borja et al.[3], the use of an hypoelastic law with constant Poisson’s ratio in the context of the Modified Cam Clay may produce that closed-loop stress paths may result in a non-conservative elastic behavior; therefore, at the end of the loading path the elastic deformation might not be fully recovered. Also, hyper-elastic laws underpin the formulation of large-strain elastoplasticity [17]. By using this theory, the constitutive model is inherently frame-indiferent [17] and algorithmic objective [9].

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Published on 01/01/2019

DOI: 10.1016/j.compgeo.2019.01.025
Licence: CC BY-NC-SA license

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